Jumper cable amp rating

[12vdc]

Kung dead na talaga baterya as in 0v then it could be considered as resistive load hence, series ang circuit mo. But kung dead ang baterya pero may e.g. 10v pa then parallel ang connection mo kasi source pa din yan kahit depleted.

Initially resistive(it will spark), since the good battery will pass current on the low V battery. The voltage will then "equalize" to 12V.

Possible lang maging 0V kung "full short" as in zero ohms. Lahat ng bagay may electric potential, parang capacitor.

[uls]

omg jumper cable lang ang tpoic umabot ng 6 pages

[12vdc]

You test a battery voltage using a Volt Meter.

You test battery current either using a constant load and timing the rate of discharge thru an ammeter

OR if you have the proper tool, use a battery tester that sends high frequency signal to compute the internal impedance.

Usual car scenario is wala na yung current holding capacity, kahit anong charge it doesnt hold madali madischarge.

[confused shoes]

Kung dead na talaga baterya as in 0v then it could be considered as resistive load hence, series ang circuit mo. But kung dead ang baterya pero may e.g. 10v pa then parallel ang connection mo kasi source pa din yan kahit depleted.

Tama, pag source sila parehas, then that is parallel.

But even the live battery (12v) will become a load if the car has been started where the alternator will become a source.

[miked]

tama na plis! nosebleed nako sa usapan nyo.......

[confused shoes]

^^

kung ang flashlight mo 3 D-battery tapos isa sa tatlong battery ay patay na iilaw parin ang bulb pero mahina

yan ang point mo

Tatlong conditions yan sir.
1. Patay ang baterya (short)
2. Patay ang baterya (open)
3. Patay ang baterya (low batt)

Condition #2, hindi iilaw si flashlight.

[12vdc]

Tama, pag source sila parehas, then that is parallel.

But even the live battery (12v) will become a load if the car has been started where the alternator will become a source.

It will "equalize" to charging voltage. The charging system will dictate the "trickle" charge that is about 13.8V ideally. Trickle charge is charging a fully charged battery at a rate of its self discharge rate to maintain a fully charged condition.

[Retz]

Initially resistive(it will spark), since the good battery will pass current on the low V battery. The voltage will then "equalize" to 12V.

Possible lang maging 0V kung "full short" as in zero ohms. Lahat ng bagay may electric potential, parang capacitor.

Un na nga ang puntos ko kanina sir. Prove to me that the dead battery acts as a purely resistive load then payag ako na series connection tawag dyan. Pero kung hindi, parallel pa din yan.

[12vdc]

Tatlong conditions yan sir.
1. Patay ang baterya (short)
2. Patay ang baterya (open)
3. Patay ang baterya (low batt)

Condition #2, hindi iilaw si flashlight.

Another condition sir, yung isang battery binaligtad.. Yan ginagawa nung magaling na manong guard ng building namin, para daw ma conserve yung energy.
Pinagalitan ko nga

[confused shoes]

After learning Thevenin's Theorem ... they also teach Norton's Theorem which states

Any linear electrical network with voltage and current sources and only resistances can be replaced at terminals A-B by an equivalent current source Ino in parallel connection with an equivalent resistance Rno.

Correct because the two current sources are called "source" or "parallel sources".

[uls]

hahaha

amazing thread

[confused shoes]

Another condition sir, yung isang battery binaligtad.. Yan ginagawa nung magaling na manong guard ng building namin, para daw ma conserve yung energy.
Pinagalitan ko nga

Ok a. . . .

[Retz]

^

si c4u na lang kulang dito para kumpleto na.

[12vdc]

^ Gradweyt na sya dito. Nagamit din naman nya yung jumper cable to isolate the battey eh.

[uls]

hahaha

nag jumper si cathy followed step by step instructions pa wala nangyari

[boytsiks]

Un na nga ang puntos ko kanina sir. Prove to me that the dead battery acts as a purely resistive load then payag ako na series connection tawag dyan. Pero kung hindi, parallel pa din yan.

A dead battery will act as a load when in parallel with another battery because the good battery will pass current to the dead one. Parang ichacharge nya yung low/ dead battery. In return, malelessen yung current capacity (A-hr) ng good battery.

A dead battery will not be source since kulang ang capacity nya.

[valskie01]

seriously. bakit kailangan malaman ng mga tsikoteer dito sa thread na ito kung series or parallel

ito ano comment niyo dito?

from my car's manual

caution:do not connect the jumper cable from the negative terminal of the booster battery to the negative terminal of the discharged battery. this can cause the discharged battery to overheat and crack, releasing battery acid.

[confused shoes]

seriously. bakit kailangan malaman ng mga tsikoteer dito sa thread na ito kung series or parallel

ito ano comment niyo dito?

from my car's manual

caution:do not connect the jumper cable from the negative terminal of the booster battery to the negative terminal of the discharged battery. this can cause the discharged battery to overheat and crack, releasing battery acid.

No sense, kasi nakakabit parehas sa car chassis yan. Baka may karugtong pang statement yan, sir. Or may ibang conditions like naka disconnect yung battery.. .

Saan naka connect yung positive ng discharged baterya? Negative terminal lang kasi ang concern nya. So pag walang connection yung positive. Parang wala.

[uls]

we jump start units almost everyday (24V heavy machines with 2 4D batteries)

negative terminal jumper cable to negative terminal

never experienced "discharged battery to overheat and crack, releasing battery acid"

[12vdc]

seriously. bakit kailangan malaman ng mga tsikoteer dito sa thread na ito kung series or parallel

ito ano comment niyo dito?

from my car's manual

caution:do not connect the jumper cable from the negative terminal of the booster battery to the negative terminal of the discharged battery. this can cause the discharged battery to overheat and crack, releasing battery acid.

Just correcting the term sir.


The manufacturer is just warning for possibilities so that you couldnt sue them incase accidents happen. Dead battery could be "shorted" or fully drained that it will draw so much current overheating the battery. But in real life, seldom mangyari ang shorted battery. And with the advent of AGM, GEL, and sealed types, less ang chances of spillage. The most is mag crack.

I've seen cracked and bloated batteries but this is due to overcharging, nadadamay ibang battery in this case.