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November 9th, 2006 06:42 PM #21
Yes. Hindi naman yung gulong ang nagpapaandar dun sa eroplano eh, yung thrust nung engine(s). Bibilis lang ikot ng gulong nung eroplano.

November 9th, 2006 06:42 PM #22
But the keyword here is lift. There is no lift because the plane is stationary, and there is no mention of any wind so we will assume there isn't any. Hence, no wind, no Bernoulli effect, no lift, regardless of the condition of the wheels of the plane.
And one important thing the question asked was would there be lift with the conveyor belt being driven opposite the plane's direction, meaning if the plane faces to the left, the conveyor belt turns clockwise. If the conveyor belt pushed the plane forward, meaning if the directions were not opposite each other, then yes, there would be lift if the velocity was high enough to produce a lower pressure above the wings and a higher pressure below the wings, to create lift.
Mathematically speaking, if the velocity of the plane were V, and the velocity in respect to the conveyor belt was V (opposite in direction but having the same magnitude), then they will cancel each other out, so the plane will be stationary. The only way there will be lift is if there is wind going across the wings, and the only 2 ways to achieve it are by moving the plane forward (which does not happen) or by having a huge fan blow the air towards the plane to simulate its actual speed. Of course, the latter will not take off too, because it will just hover for a few seconds and eventually fall back to the ground (no momentum).Last edited by mbeige; November 9th, 2006 at 06:47 PM.

November 9th, 2006 06:45 PM #23

November 9th, 2006 06:53 PM #24
Assuming the wheel bearings of the plane have negligible friction, and considering that the original question stated that:
This conveyor has a control system that tracks the plane's
speed and tunes the speed of the conveyor to be exactly the same (but
in the opposite direction) instantly.

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November 9th, 2006 06:54 PM #25exactly alpha one!
given enough thrust i dont think a plane/missile/projectile will even need a runway.

November 9th, 2006 06:56 PM #26
It's an airplane, not a rocket. Even if it had thrust, it needs lift to take off! Thrust will only push it forward, but what happens here? Negligible yung friction and the conveyor belt instantly brings the velocity to zero dahil yun ang nakalagay sa condition ng tanong.

November 9th, 2006 06:58 PM #27
The velocity of the plane and the runway can't cancel each other out. Velocity is change in position, and the plane's position is independent of that of the treadmill este runway. Kung two equal but opposite "velocities" acting on the plane, saka sila magkacancel out.
Now, if the question was that the runway will exert a force opposite that and acting on the airplane, then the plane will not move.
Pero kung speed lang nung runway ang pinaguusapan, lilipad yung eroplano.
At the moment of takeoff: Relative to the wind, airplane will be running at takeoff speed, the runway will be running at takeoff speed towards the other direction. Relative to each other, the plane and the runway will be passing each other at TWICE the take of speed.

November 9th, 2006 07:03 PM #28
Here's where the trick comes in. Sabi sa tanong yung speed ang matched hindi yung force. Kung umaandar yung eroplano 1MPH, yung runway umaandar ng 1MPH pabalik. Relative to each other, they're running at 2MPH.
Nowhere in the question did it say that the wind moves in the opposite direction. Assuming "no wind" (wind ang '0mph' reference) plane moves at 1MPH against the wind, runway moves at 1MPH against the wind in the opposite direction, plane and runway moves against each other at 2MPH.

November 9th, 2006 07:07 PM #29
The plane's position, relative to the conveyor belt, remains the same because the force that the plane exerts on the conveyor belt is cancelled by the conveyor belt applying the same force but opposite in direction to the plane via the wheels. Therefore, the wheels rotate and act as a bearing, allowing the plane to remain on top of the conveyor belt. Like it is stated on the question, once the plane gains a certain speed, it is instantly brought to zero by the conveyor belt because it is already stated that the belt will instantly provide the same speed but opposite in direction. Hence, the plane's speed relative to the conveyor belt is zero.
The runway can only exert the force to the wheels, not to the plane itself, because the wheels will be freewheeling.
What do you mean?
It cannot take off because it is stationary! Relative to the wind, the plane is stationary. Buti sana kung totoong runway yon, then yes. That's because the runway in this situation is moving on the opposite direction.

November 9th, 2006 07:08 PM #30
Exactly. The conveyor matches the airplane's speed. Thus, the airplane moves forward at 30 mph. Instantly, the runway moves backwards at 30 mph. The wheels of the plane are now moving at 60 mph.
We have to consider this as a frictionless exercise, as by having the conveyor move at exactly the same time as the plane, you're creating a fictional universe in which there is no lightspeed delay anyway... :hysterical:
In the absence of friction in the wheels or the conveyor bearings, all that happens is the wheels move twice as fast, the belt moves one way, the plane moves another, and it'll take off... with exactly the same amount of thrust it would have needed to take off from a stationary runway.
Ang pagbalik ng comeback...
I tried scanning it through google translate. Not sure how accurate it is, but the words that would...
"BADUY" car thread