Quote Originally Posted by Manilablock View Post
Pag asa mall during demo papakita sayo na gumagana, pero sa mga nakabili meron ba talaga improvement sa bill nyo

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Sir, this gadget is a power factor correction unit which improves the power factor.. the Power factor is a ratio of the Real Power ( Kw o Watts ) to Apparent power ( kVA or VA). Please be inform that Meralco is billing us only for the Real Power in kW or watts being consumed in a length of time ( Kw-HR) and not for the apparent power (kVA) nor for improving the Power Factor. ( unlike in industrial or commercial user).. during the Demo, the guy will show us a multimeter on which they will measured the current consumed by the motors before and after the gadget was installed..
for example, a 1 hp or 746 watts motor, power factor ( PF) =0.8, connected in the 230 Volts outlet, initially will read about 4 A (amperes).. then when the gadget was installed, the readings will become 3.2A ,, so they will point to us on the 0.8 A reduction after the gadget was installed...or simply a 20% decrease in consumption and literally they will translate it as a saving.. but the truth is, we are still using the same motor that consumes 746 watts ( real power) and Meralco will bill us for that real power only and not on the reduce in Current (A) reading due to improvement of the power factor...

How it works, here is the formula / relationship of the power factor to ( kW) real power and (kVA)apparent power:

*Real Power (Meralco bill is based on this only as they are using only kw-hr meter, not a KVA-hr meter )
P = V (voltage) x I (current in amperes) x P.F, ( for motor, P.F = 0.6 to 0.8 )

*Apparent Power
S = V (voltage) x I (current in amperes) ....

for our example:
P = 746 watts,
the current reading is
I = 746 watts / ( 230 Volts x 0.8) = 4 Amperes ( this what the Ammeter will read and being shown to us during the demo)
using the original value of the current, we can compute for the apparent power:
S= V x I, = 230 Volts x 4 Amperes = 920 VA ( the apparent power and we are not billed by Meralco on this )

then when the gadget is applied, it will improve the P.F. from 0.8 to almost equal to 1. so the real Power (P) and apparent power (S) will now be almost equal.
P = 746 watts ; S = 746 VA. but the current will now change since the voltage is still the same, 230 Volts..,

as for the new value of S, we check the new value of the current,
I = 746 VA / ( 230 Volts )
I = 3.2 Amperes only.. ( this the value they showing us and its 20% lower than the previous reading)

it clearly indicates that there's a reduction in the current ( A- Amperes) when the power factor improves ( from 0.8 to 1), but the power consumptions (Real Power, which the actual power required by the motor to run ) is still the same which is 746 watts, and based on that real power only Meralco is billing us.