Will the Airplane Fly??????????

[Alpha_One]

The plane's position, relative to the conveyor belt, remains the same because the force that the plane exerts on the conveyor belt is cancelled by the conveyor belt applying the same force but opposite in direction to the plane via the wheels. Therefore, the wheels rotate and act as a bearing, allowing the plane to remain on top of the conveyor belt. Like it is stated on the question, once the plane gains a certain speed, it is instantly brought to zero by the conveyor belt because it is already stated that the belt will instantly provide the same speed but opposite in direction. Hence, the plane's speed relative to the conveyor belt is zero.



The runway can only exert the force to the wheels, not to the plane itself, because the wheels will be freewheeling.



What do you mean?



It cannot take off because it is stationary! Relative to the wind, the plane is stationary. Buti sana kung totoong runway yon, then yes. That's because the runway in this situation is moving on the opposite direction.

The plane's position, relative to the runway, does change. In fact, their speed relative to each other would be double (not zero) that of a stationary runway.

Paragraph 2: You just proved my point. The wheels are indeed freewheeling, they have absolutely nothing to do with the speed of the airplane! The runway exerts absolutely no force on the airplane itself (other than the wheels)!

Paragraph 3: What I mean is, the speed of the runway has absolutely nothing to do with the speed of the airplane itself. The wheels will be spinning TWICE as fast, but the plane goes forward as usual.

Paragraph 4: In fact, from a completely logical/philosophical perspective, such a scenario (the plane being stationary) is impossible unless the runway is stationary too. Premise: for the runway to do xMPH, the plane must do xMPH in the other direction. From a physics standpoint, it's also completely possible, the wheels would simply spin twice as fast. Other than that everything else is exactly the same as a perfectly normal, stationary runway.