Jumper cable amp rating

**12vdc** · July 11th, 2013 11:28 PM

Originally Posted by Retz

Kung dead na talaga baterya as in 0v then it could be considered as resistive load hence, series ang circuit mo. But kung dead ang baterya pero may e.g. 10v pa then parallel ang connection mo kasi source pa din yan kahit depleted.

Initially resistive(it will spark), since the good battery will pass current on the low V battery. The voltage will then "equalize" to 12V.

Possible lang maging 0V kung "full short" as in zero ohms. Lahat ng bagay may electric potential, parang capacitor.

**uls** · July 11th, 2013 11:28 PM

omg jumper cable lang ang tpoic umabot ng 6 pages

**12vdc** · July 11th, 2013 11:29 PM

You test a battery voltage using a Volt Meter.

You test battery current either using a constant load and timing the rate of discharge thru an ammeter

OR if you have the proper tool, use a battery tester that sends high frequency signal to compute the internal impedance.

Usual car scenario is wala na yung current holding capacity, kahit anong charge it doesnt hold madali madischarge.

**confused shoes** · July 11th, 2013 11:30 PM

Originally Posted by Retz

Kung dead na talaga baterya as in 0v then it could be considered as resistive load hence, series ang circuit mo. But kung dead ang baterya pero may e.g. 10v pa then parallel ang connection mo kasi source pa din yan kahit depleted.

Tama, pag source sila parehas, then that is parallel.

But even the live battery (12v) will become a load if the car has been started where the alternator will become a source.

**miked** · July 11th, 2013 11:35 PM

tama na plis! nosebleed nako sa usapan nyo.......

**confused shoes** · July 11th, 2013 11:35 PM

Originally Posted by uls

^^

kung ang flashlight mo 3 D-battery tapos isa sa tatlong battery ay patay na iilaw parin ang bulb pero mahina

yan ang point mo

Tatlong conditions yan sir.
1. Patay ang baterya (short)
2. Patay ang baterya (open)
3. Patay ang baterya (low batt)

Condition #2, hindi iilaw si flashlight.

**12vdc** · July 11th, 2013 11:37 PM

Originally Posted by confused shoes

Tama, pag source sila parehas, then that is parallel.

But even the live battery (12v) will become a load if the car has been started where the alternator will become a source.

It will "equalize" to charging voltage. The charging system will dictate the "trickle" charge that is about 13.8V ideally. Trickle charge is charging a fully charged battery at a rate of its self discharge rate to maintain a fully charged condition.

**Retz** · July 11th, 2013 11:40 PM

Originally Posted by 12vdc

Initially resistive(it will spark), since the good battery will pass current on the low V battery. The voltage will then "equalize" to 12V.

Possible lang maging 0V kung "full short" as in zero ohms. Lahat ng bagay may electric potential, parang capacitor.

Un na nga ang puntos ko kanina sir. Prove to me that the dead battery acts as a purely resistive load then payag ako na series connection tawag dyan. Pero kung hindi, parallel pa din yan.

**12vdc** · July 11th, 2013 11:45 PM

Originally Posted by confused shoes

Tatlong conditions yan sir.
1. Patay ang baterya (short)
2. Patay ang baterya (open)
3. Patay ang baterya (low batt)

Condition #2, hindi iilaw si flashlight.

Another condition sir, yung isang battery binaligtad.. Yan ginagawa nung magaling na manong guard ng building namin, para daw ma conserve yung energy.
Pinagalitan ko nga

**confused shoes** · July 11th, 2013 11:46 PM

Originally Posted by kinyo

After learning Thevenin's Theorem ... they also teach Norton's Theorem which states

Any linear electrical network with voltage and current sources and only resistances can be replaced at terminals A-B by an equivalent current source Ino in parallel connection with an equivalent resistance Rno.

Correct because the two current sources are called "source" or "parallel sources".