Results 1 to 10 of 13
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August 15th, 2009 12:18 PM #2
one of my hatest topic, PROVING. lalo na yun chinese proving namin dati, naging sabaw utak ko hahaha..
sorry JJ, nakalimutan ko na ito
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August 15th, 2009 12:53 PM #4Given : m<JKL = m<NKM
THEREFORE: m<JKL = m<NKM
SINCE : <LKM = <LKM
THEREFORE: m<JKL + <LKM = m<JKM
ALSO : m<NKM + <LKM = m<NKL
THEREFORE: m<JKM = m<NKL
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August 15th, 2009 01:21 PM #5
Post ko lang dito yung itinuro ko kay JJ sa YM:
prove mo lang na m<JKL + m<LKM = m<NKM + m<LKM (adding same value to both sides of equation)
parang since x = y, it follows that x + i = y + i for any value of i.
Now, since:
m<JKL + m<LKM = m<JKM
and
m<NKM + m<LKM = m<NKL , (ANGLE ADDITION POSTULATE)
Therefore, by substitution, m<JKM = m<NKL
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August 15th, 2009 04:17 PM #7
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August 15th, 2009 04:25 PM #8
eto yun final 2 column proof ko:
Statement reason
1. m<JKL = m< NKM Given
2. m<LKM = m<LKM Reflexive Property of equality
3. m<JKL + m<LKM = m<JKM
m<NKM + m<LKM = m<NKL Angle addition postulate
4. m<JKM = m<NKL Substitution
edit: formatting seem to appear broken..kayo nalang umintindi.. heheLast edited by JJCarEnthusiast; August 15th, 2009 at 04:28 PM.
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August 15th, 2009 04:27 PM #9
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August 20th, 2009 09:18 AM #10
Puwede i try, 1. Palit air filter 2. Linis throttle body 3. Linis MAF sensor 4. Check spark...
high idle RPM at engine start