do you know how to compute elec consumption?

[woohoo]

http://www.thinkgeek.com/gadgets/travelpower/7657/



This gadget would be handy but I think it only works on 110 volts.

It *is* handy. My neighbor has one. Too bad it only works on 110V (120V). All our efforts to search one that works on 220V only found us some INDUSTRIAL-grade ones.

... but today, this same neighbor showed me his newly-purchased VoltCraft Plus Energy Logger 3500. He bought it from Alexan for Php1,500.00 but their website doesn't list it.

But I found it on the internet anyway: http://www.conrad-international.com/?article=125323

I'll buy one myself later.

[jjmd3_787]

If my memory serves me right, here are the formulas:

1. number of watts / 1000 to get kilowatt per hour consumption
2. multiply by number of hours used in a day
3. multiply by number of days used in a month
4. multiply by cost per KWh (depends on the current rate established by your provider)

[venerito]

Out of the given information below, please help me identify how much is the total kilowatt/hr share of the sub-meter out of the total kw/hr Mother meter per month and please show how to compute.

Please note that information were gathered on the same date per month:

Sub meter Mother meter
Feb 2010 19726 600
Mar. 2010 28806 1631

Appreciate your kind help.

[woohoo]

Out of the given information below, please help me identify how much is the total kilowatt/hr share of the sub-meter out of the total kw/hr Mother meter per month and please show how to compute.

Please note that information were gathered on the same date per month:

Sub meter Mother meter
Feb 2010 19726 600
Mar. 2010 28806 1631

Appreciate your kind help.

I think your meter readings are reversed. I think the mother meter's readings are the large numbers (28806 - 19726 = 9,080 KWH), and the submeter's are the small figures (1631 - 600 = 1,031 KWH).

My golly, those are large numbers!

The simplest way to compute for the submeter's share is by determining the average cost that was billed to the mother meter (pesos / kwh) and multiplying the submeter's consumption by that quotient.

Let's say your March bill for the mother meter is 75,000. Your average rate is 75000/9080 = 8.26. Therefore you may charge the submeter 8.26 * 1,031 = 8,516.06.

HTH.


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