do you know how to compute elec consumption?

[kinesis]

Hi guys, i would like to seek help to those who knows how to compute electrical consumption? computations will start from getting load from the electrical appliances. ex electrical fan, 40 watts bulb etc.... up to how to convert the consumption to pesos.

kaya ko po pala ito gusto malaman dahil po sa this coming month im be sharing my electrical meter to my cousin and due to that we want to compute how much electricity will be adding to my billing since may mga appliances siyang dala.

thank you in advance

[oj88]

The electric company charges us per kilowatt-hour (kWh). The current rate (pesos/kWh) is on your bill.

To get your consumption, use this formula:

Power consumption of appliance (Watts) x Number of hours used (H) = Watt-Hour (Wh)

So for your 40W bulb operating at 5 hours per day:

40W x 5 hrs = 200 Watt-hours or 0.200 kWh

Multiply that by 30 days (1 month's consumption), would get you 6 kWh

Multiply that with the current rate in Pesos and you'll have the cost of operating that bulb in a month.

[v6dreamer]

Simple.

1000 watts is 1kw
1kw for 1 hour is 1 kw-hr

Watts are a unit of power, which is the rate of using energy. So watts are joules per second.

A more useful, but confusing unit of energy is the watt-hour, which you can get by multiplying number of watts by number of hours.

So, if your appliance is consuming 40 watts and you want to know how much energy that is in 24 hrs (one day), then multiply by 24 to get 960 watt-hours.

If electricity costs 10 cents per kW-hr, which is 10 cents per 1000 watt-hours, then the applicance costs you:

960 watt-hours x 10 cents /1000 watt-hours = 9 pesos and 60 cents. for the period of 24 hrs.

[Taurus]

You may also need to consider the other charges, such as FCA and miscellaneous fees.
there is also a range where the rate may change depending on the limit of your total consumption. e.g. you may be charge in a lower rate if you only consume less than 100 kW/H.

[rst619]

well tama iyung mga sinabi nila pero hindi accurate.

Ex a 40w Fluorescent lamp really consumes around 50w. a 1.5 hp aircon consumes roughly 1Kw/hr pero depende din sa load ng compressor.

so baka malugi ka sa computation. and besides paano mo maoorasan ang hrs or use ng appliances di ba?

Mas madali siguro bili ka na lang ng sub-meter (around 600-700) ito, then after the submeter dun mo ipaconnect lahat ng appliances niya para accurate.

BTW you may also visit www.meralco.com.ph may appliance calculator sila dun.

[ghosthunter]

http://www.thinkgeek.com/gadgets/travelpower/7657/



This gadget would be handy but I think it only works on 110 volts.

[v6dreamer]

The computation is just an example not the exact value of how many kw-hr and cost amount used on every household. How to know your monthly kw-hr consumption, by reading it your elec. meter.

Here's what you should do.... start of the month on any given cut-off day by your elec. company. Check your meter number, say its 5,090 then at end of month (given day) check it again say its 6,937= 1,847 kw an hour used.
So the diff. is 1,847 kw-hr. x cost per kw-hr. = (?). That is the cost of electricty in a month not including tax and misc. fee.

[woohoo]

well tama iyung mga sinabi nila pero hindi accurate.

Ex a 40w Fluorescent lamp really consumes around 50w. a 1.5 hp aircon consumes roughly 1Kw/hr pero depende din sa load ng compressor.

so baka malugi ka sa computation. and besides paano mo maoorasan ang hrs or use ng appliances di ba?

Mas madali siguro bili ka na lang ng sub-meter (around 600-700) ito, then after the submeter dun mo ipaconnect lahat ng appliances niya para accurate.

BTW you may also visit www.meralco.com.ph may appliance calculator sila dun.

Good idea! i-split mo yung consumption niya using a submeter, kung gusto mo ng accuracy. Then get the percentage of his consumption (use v6dreamer's method of meter reading) when you "mother" meter's bill comes. Apply the percentage to the bill amount.

[dbuzz]

bro kung share kayo sa elec but then sa kabilang building sya madili lang solusyon . iyan ay ang magpakabit ng sub meter. you can buy it at most elec. hardware store. tapos ang problema mo.

but then kung sa iisang bahay lang kayo medyo maraming dapat tingnan. (maliban sa sariling kwarto), dapat ma-take into consideration ang mga common utililities. -yung mga electrical appliances-(ilaw,aircon/elec.fan) sa hallway, cr, dining, sala... kasi nga nakigamit din sya nun.

para sa mabilisang solusyon... pababayaran mo muna sa kanya ang diff. ng nakaraang billing(na wala pa sya) with billing na kasama na sya.

o di kaya just say "uy dagdag ka muna ng 1kPesos/month sa elec bill."

kanina sa palengke may tindera doon at may soft drinks cooler siya. tinanong ko kung magkano charge ng management .. 50pesos/per day.

[Cult Zero]

well tama iyung mga sinabi nila pero hindi accurate.

Ex a 40w Fluorescent lamp really consumes around 50w. a 1.5 hp aircon consumes roughly 1Kw/hr pero depende din sa load ng compressor.

so baka malugi ka sa computation. and besides paano mo maoorasan ang hrs or use ng appliances di ba?

Mas madali siguro bili ka na lang ng sub-meter (around 600-700) ito, then after the submeter dun mo ipaconnect lahat ng appliances niya para accurate.

BTW you may also visit www.meralco.com.ph may appliance calculator sila dun.

yep, just get a sub-meter para yun actual usage ang makukuha mo.

ito yun sinasabi ni rst na appliance calculator http://www.meralco.com.ph/ces/ces.jsp

[woohoo]

http://www.thinkgeek.com/gadgets/travelpower/7657/



This gadget would be handy but I think it only works on 110 volts.

It *is* handy. My neighbor has one. Too bad it only works on 110V (120V). All our efforts to search one that works on 220V only found us some INDUSTRIAL-grade ones.

... but today, this same neighbor showed me his newly-purchased VoltCraft Plus Energy Logger 3500. He bought it from Alexan for Php1,500.00 but their website doesn't list it.

But I found it on the internet anyway: http://www.conrad-international.com/?article=125323

I'll buy one myself later.

[jjmd3_787]

If my memory serves me right, here are the formulas:

1. number of watts / 1000 to get kilowatt per hour consumption
2. multiply by number of hours used in a day
3. multiply by number of days used in a month
4. multiply by cost per KWh (depends on the current rate established by your provider)

[venerito]

Out of the given information below, please help me identify how much is the total kilowatt/hr share of the sub-meter out of the total kw/hr Mother meter per month and please show how to compute.

Please note that information were gathered on the same date per month:

Sub meter Mother meter
Feb 2010 19726 600
Mar. 2010 28806 1631

Appreciate your kind help.

[woohoo]

Out of the given information below, please help me identify how much is the total kilowatt/hr share of the sub-meter out of the total kw/hr Mother meter per month and please show how to compute.

Please note that information were gathered on the same date per month:

Sub meter Mother meter
Feb 2010 19726 600
Mar. 2010 28806 1631

Appreciate your kind help.

I think your meter readings are reversed. I think the mother meter's readings are the large numbers (28806 - 19726 = 9,080 KWH), and the submeter's are the small figures (1631 - 600 = 1,031 KWH).

My golly, those are large numbers!

The simplest way to compute for the submeter's share is by determining the average cost that was billed to the mother meter (pesos / kwh) and multiplying the submeter's consumption by that quotient.

Let's say your March bill for the mother meter is 75,000. Your average rate is 75000/9080 = 8.26. Therefore you may charge the submeter 8.26 * 1,031 = 8,516.06.

HTH.


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