i tried calculating the amount of current this scheme would take, way back when i was a kid with impractical ideas.
i don't really see how Dingle's contraption can work, because as mazdamazda has said, the amount of energy you get from burning the h2 + o2 is less than the amount you have to spend to split the water. however, if the aim is to improve efficiency of combustion (a la acetone) then perhaps that would work.
using Faraday's constant (
not Faraday's Law -- that one relates to electromagnetism) we know that 96,485 Coulombs is 1 Faraday. And 1 Faraday is 1 Mole of electrons. It takes 2 Moles of electrons to produce 1 Mole of Hydrogen.
So, 192970 Coulombs to produce 1 mole of hydrogen.
Let's say you're aiming for a 1% (volumetric) mix of hydrogen in your fuel. If you have say a 2.0L displacement vehicle with 4 cylinders, at a nominal speed of 2000rpm, that's about 500mL * 2000rpm = 1000L of gases moving through the engine in one minute, or 17L per second. Your 1% hydrogen is 170mL of hydrogen per second.
At STP, a standard mole of gas is 22.4L (of course an engine is hotter than STP, but the pressure is also higher). Let's just assume STP for sake of argument.
170mL is therefore 0.0076 moles. Using Faraday's constant, we need
1465 Coulombs to produce this much hydrogen.
Remember that the ampere (current) is actually Coulombs per second. Since we need 170mL of hydrogen in
one second we need a current through our electrolysis cell of
1465 amperes!!! Now where are you gonna get that much current?!?!?!
As an aside, you will note that what determines the speed of electrolysis is
not the voltage -- it's the current. The voltage is irrelevant so long as you can get the current.
Now 1465 amperes is a huge amount of current. You cannot get that out of a car battery or alternator. The only way to get this much current is to step down the voltage to a very low value (say 0.5 volts). Since the car battery is DC, you have an additional problem there: energy loss in the DC-DC converter.
Also, it's better to use AC for electrolysis rather than DC (but low frequency). Because using DC, the cathode and anode get corroded really fast.
Anyway: how do you get anywhere near 1465 amperes of current?
1) You have to have the cathode and anode
very close to each other -- that way the resistance of the water is low, and the current is very high. Also you should have lots of cathode/anode pairs in parallel, to reduce the resistance even further.
2) As I said, step down the voltage. If you can get the resistance of the cell low enough so that say 1.2V is enough, then your current requirement (from the battery) drops to 146 Amperes -- still a goodly quantity, but at least now it's in the realm of possibility.
You have to calculate the resistance of the electrolyte, to get 146A at 1.2V the resistance of the cell cannot be above 0.01 ohms. That's TINY. Your wiring alone would probably contribute more resistance. Practically, to get a resistance that low you would need a
huge cell with very close tolerances, because large plate area + small plate separation equals small resistance.
You would need a pump to recirculate the electrolyte: you cannot use pure water, you have to add salt or baking soda to reduce the resistance. If you do this, crap/deposits will build up on the plates. If your plate separation is small, the plates will eventually short out. So you need a powerful pump to keep the electrolyte moving and prevent buildup of those solid deposits.
It would be better to somehow tap the AC output of the alternator right away (before the alternator regulator converts it to DC) so you bypass the DC-DC conversion which is very inefficient. Then you'd have a custom-built transformer to convert the ~100V AC from the alternator down to your 1V DC at very high current.
All in all, I don't know if all this is practical!