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Verified Tsikot Member
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May 4th, 2005 03:41 PM #1chiefs and chiefesses
i need your help in determining what amp to use with these subs that i have with me.
specs of the subs are as follows:
Subwoofer Specifications 12IB4
Fs (free-air resonance): 40.5 Hz
Qts (total speaker “Q”): 0.634
Qes (electrical “Q”): 0.673
Qms (mechanical “Q”): 10.967
Vas (equivalent compliance): 3.97 112.4
Xmax (linear excursion one-way): 0.288 7.3
Effi ciency (1W/1m)*: 92.2 dB
Sd (effective piston surface area): 78.5 0.0506
Re (DC resistance): 6.07 Ω
Znom (nominal impedance): 8 Ω
Pt (continuous thermal power handling): 125 Watts
Wired directly to the amplifier:
A single 8Ω speaker will present a 8Ω load.
With speakers wired in parallel:
Two 8Ω speakers will present a 4Ω load.
With speakers wired in parallel:
Three 8Ω speakers will present a 2.7Ω load.
thank you very much for the help! nalilito kasi ako sa "8Ω" what does this mean?Last edited by Trojan; May 4th, 2005 at 03:43 PM.
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May 4th, 2005 03:44 PM #2
That is the symbol for ohms... You need an amp that can put out 125W on an 8ohm load.
Free air pala yang ganyang sub, just found it on the JL website. That's a real space saver.Last edited by the_wildthing; May 4th, 2005 at 03:48 PM.
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Verified Tsikot Member
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May 4th, 2005 03:47 PM #5wala pa akong amp. maghahanap pa. kaya nga i'm asking around muna kung ano ang good match with these before i start looking for an amp.
thanks!
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Verified Tsikot Member
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- Apr 2005
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- 26
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May 4th, 2005 03:49 PM #7
total JL naman yan. try finding a 300 watts amp. yung rockford, or audiobank... audiobank mas ok sa budget mo...
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May 4th, 2005 03:51 PM #8
mmm... you would need a lot of juice to power those babies. whats the RMS rating? so that we can narrow down your choices.
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May 4th, 2005 03:54 PM #9
-ILD-
kaya mo yan. magkano kaya ang budget ni trojan?! and kung brabd concious ba sya?!
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May 4th, 2005 03:56 PM #10
Ah... so having two, and wiring it in parallel will give you a 4 ohm load seen by the amp... now to work out the power required ... 250W?
Damn I have to read up on my Physics again.
Given that the current will simply split into the two loads of equal resistance, and P is simply I^2 R, can you just double P? You also get something like 250W if you double I, square it and multiply by 4 to get P.
Haaay... wala bang Physics guru dito?Last edited by the_wildthing; May 4th, 2005 at 04:05 PM.
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